Sanibel is a city located in Lee County, Florida. Sanibel has a 2025 population of 6,350 . Sanibel is currently declining at a rate of -0.13% annually and its population has decreased by -0.61% since the most recent census, which recorded a population of 6,389 in 2020.
The average household income in Sanibel is $226,596 with a poverty rate of 7.65%. The median age in Sanibel is 68.2 years: 68.8 years for males, and 66.7 years for females. For every 100 females there are 85.1 males.
Data after 2023 is projected based on recent change
The racial composition of Sanibel includes 95.3% White, and smaller percentages for Two or more races, Asian, Black or African American, other race, Native American and multiracial populations.
White (95.3%)
Two or more races (2.12%)
Asian (1.12%)
Black or African American (0.86%)
Other race (0.36%)
Native American (0.23%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 6,101 | 95.3% |
| Two or more races | 136 | 2.12% |
| Asian | 72 | 1.12% |
| Black or African American | 55 | 0.86% |
| Other race | 23 | 0.36% |
| Native American | 15 | 0.23% |
Married
Widowed
Divorced
Separated
Never Married
Sanibel's average per capita income is $47,786. Household income levels show a median of $122,730. The poverty rate stands at 7.65%.
Name | Median | Mean |
|---|---|---|
| Married Families | $166,282 | - |
| Families | $160,577 | $260,749 |
| Households | $122,730 | $226,596 |
| Non Families | $54,063 | $141,645 |
Average Income
Median Household Income
Poverty Rate