Jefferson is located in Elkhart County, Indiana. Jefferson has a 2025 population of 11,144 . Jefferson is currently growing at a rate of 0.45% annually and its population has increased by 1.34% since the most recent census, which recorded a population of 10,997 in 2020.
The average household income in Jefferson is $128,278 with a poverty rate of 3.67%. The median age in Jefferson is 32.7 years: 33.6 years for males, and 32.2 years for females. For every 100 females there are 92.9 males.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 88.33% White, and smaller percentages for other race, Black or African American, Asian, Native American, Native Hawaiian or Pacific Islander and multiracial populations.
White (88.33%)
Two or more races (9.44%)
Other race (0.79%)
Black or African American (0.68%)
Asian (0.48%)
Native American (0.19%)
Native Hawaiian or Pacific Islander (0.08%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 9,708 | 88.33% |
| Two or more races | 1,037 | 9.44% |
| Other race | 87 | 0.79% |
| Black or African American | 75 | 0.68% |
| Asian | 53 | 0.48% |
| Native American | 21 | 0.19% |
| Native Hawaiian or Pacific Islander | 9 | 0.08% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $53,141. Household income levels show a median of $112,566. The poverty rate stands at 3.67%.
Name | Median | Mean |
|---|---|---|
| Married Families | $124,602 | - |
| Families | $114,414 | $132,723 |
| Households | $112,566 | $128,278 |
| Non Families | $80,179 | $86,459 |
Average Income
Median Household Income
Poverty Rate