Seymour is a city located in Jackson County, Indiana. Seymour has a 2025 population of 21,690. Seymour is currently growing at a rate of 0.06% annually and its population has increased by 0.28% since the most recent census, which recorded a population of 21,629 in 2020.
The average household income in Seymour is $77,047 with a poverty rate of 14.42%.The median age in Seymour is 33.3 years: 29.4 years for males, and 37.4 years for females.
Data after 2023 is projected based on recent change
The racial composition of Seymour includes 68.43% White, 8.72% other race, 4.24% Asian, and smaller percentages for Black or African American, Native American, Native Hawaiian or Pacific Islander and multiracial populations.
Race | Population | Percentage (of total) |
---|---|---|
White | 14,737 | 68.43% |
Two or more races | 3,201 | 14.86% |
Other race | 1,877 | 8.72% |
Asian | 914 | 4.24% |
Black or African American | 436 | 2.02% |
Native American | 349 | 1.62% |
Native Hawaiian or Pacific Islander | 22 | 0.1% |
Married
Widowed
Divorced
Separated
Never Married
Seymour's average per capita income is $45,270. Household income levels show a median of $63,388. The poverty rate stands at 14.42%.
Name | Median | Mean |
---|---|---|
Married Families | $88,518 | - |
Families | $74,211 | $87,686 |
Households | $63,388 | $77,047 |
Non Families | $38,029 | $51,366 |
Average Income
Median Household Income
Poverty Rate