Harlan township is located in Shelby County, Iowa. Harlan township has a 2025 population of 766. Harlan township is currently declining at a rate of 0% annually and its population has decreased by 0% since the most recent census, which recorded a population of 0 in 2020.
The average household income in Harlan township is $85,665 with a poverty rate of 4.05%.The median age in Harlan township is 50.6 years: 50.5 years for males, and 51.1 years for females.
Data after 2023 is projected based on recent change
The racial composition of Harlan township includes 98.3% White, and smaller percentages for Two or more races, Black or African American and multiracial populations.
Race | Population | Percentage (of total) |
---|---|---|
White | 753 | 98.3% |
Two or more races | 10 | 1.31% |
Black or African American | 3 | 0.39% |
Married
Widowed
Divorced
Separated
Never Married
Harlan township's average per capita income is $48,672. Household income levels show a median of $59,167. The poverty rate stands at 4.05%.
Name | Median | Mean |
---|---|---|
Married Families | $101,563 | - |
Families | $91,944 | $107,831 |
Households | $59,167 | $85,665 |
Non Families | $30,455 | $44,097 |
Average Income
Median Household Income
Poverty Rate