Harlan township is located in Shelby County, Iowa Iowa. Unfortunately, the data for this location is currently limited or unavailable.
The median household income in Harlan township is $77,031 with a poverty rate of 2.78%. The median age in Harlan township is 53.7 years: 53.9 years for males, and 53.3 years for females. For every 100 females there are 76.2 males.
No data available.
The racial composition of Harlan township includes 98.81% White, and smaller percentages for Two or more races and multiracial populations.
White (98.81%)
Two or more races (1.19%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 249 | 98.81% |
| Two or more races | 3 | 1.19% |
Married
Widowed
Divorced
Separated
Never Married
Harlan township's average per capita income is $54,250. Household income levels show a median of $77,031. The poverty rate stands at 2.78%.
Name | Median | Mean |
|---|---|---|
| Married Families | $118,125 | - |
| Families | $115,833 | $104,907 |
| Households | $77,031 | $91,568 |
| Non Families | $63,750 | $54,561 |
Average Income
Median Household Income
Poverty Rate