Janesville is a city located in Bremer County, Iowa. Janesville has a 2025 population of 1,055 . Janesville is currently growing at a rate of 0.29% annually and its population has increased by 1.74% since the most recent census, which recorded a population of 1,037 in 2020.
The average household income in Janesville is $93,921 with a poverty rate of 5.75%. The median age in Janesville is 44.7 years: 44 years for males, and 45.3 years for females. For every 100 females there are 100.8 males.
Data after 2023 is projected based on recent change
The racial composition of Janesville includes 99.11% White, and smaller percentages for Two or more races, other race and multiracial populations.
White (99.11%)
Two or more races (0.69%)
Other race (0.2%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 1,003 | 99.11% |
| Two or more races | 7 | 0.69% |
| Other race | 2 | 0.2% |
Married
Widowed
Divorced
Separated
Never Married
Janesville's average per capita income is $57,574. Household income levels show a median of $84,231. The poverty rate stands at 5.75%.
Name | Median | Mean |
|---|---|---|
| Families | $110,139 | $112,865 |
| Married Families | $110,139 | - |
| Households | $84,231 | $93,921 |
| Non Families | $41,750 | $46,143 |
Average Income
Median Household Income
Poverty Rate