Oran township is located in Fayette County, Iowa. Oran township has a 2025 population of 876. Oran township is currently declining at a rate of 0% annually and its population has decreased by 0% since the most recent census, which recorded a population of 0 in 2020.
The average household income in Oran township is $114,339 with a poverty rate of 0.8%.The median age in Oran township is 52.5 years: 52.1 years for males, and 53.9 years for females.
Data after 2023 is projected based on recent change
The racial composition of Oran township includes 86.99% White, and smaller percentages for and multiracial populations.
Race | Population | Percentage (of total) |
---|---|---|
White | 762 | 86.99% |
Two or more races | 114 | 13.01% |
Married
Widowed
Divorced
Separated
Never Married
Oran township's average per capita income is $50,750. Household income levels show a median of $105,964. The poverty rate stands at 0.8%.
Name | Median | Mean |
---|---|---|
Married Families | $114,632 | - |
Families | $108,750 | $124,828 |
Households | $105,964 | $114,339 |
Non Families | $48,696 | $60,164 |
Average Income
Median Household Income
Poverty Rate