Seymour is a city located in Wayne County, Iowa Iowa. Unfortunately, the data for this location is currently limited or unavailable.
The average household income in Seymour is $52,112 with a poverty rate of 18.44%. The median age in Seymour is 51.8 years: 40.5 years for males, and 57.1 years for females. For every 100 females there are 98.6 males.
No data available.
The racial composition of Seymour includes 95.88% White, and smaller percentages for and multiracial populations.
White (95.88%)
Two or more races (4.12%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 535 | 95.88% |
| Two or more races | 23 | 4.12% |
Married
Widowed
Divorced
Separated
Never Married
Seymour's average per capita income is $40,682. Household income levels show a median of $45,000. The poverty rate stands at 18.44%.
Name | Median | Mean |
|---|---|---|
| Married Families | $67,857 | - |
| Families | $65,833 | $67,363 |
| Households | $45,000 | $52,112 |
| Non Families | $35,313 | $33,172 |
Average Income
Median Household Income
Poverty Rate