Sanford is located in Broome County, New York. Sanford has a 2025 population of 2,181 . Sanford is currently growing at a rate of 0.05% annually but its population has decreased by -2.2% since the most recent census, which recorded a population of 2,230 in 2020.
The average household income in Sanford is $90,582 with a poverty rate of 14.23%. The median age in Sanford is 52.5 years: 52.1 years for males, and 53.5 years for females. For every 100 females there are 104.7 males.
Data after 2023 is projected based on recent change
The racial composition of Sanford includes 97.28% White, and smaller percentages for other race, Two or more races, Black or African American, Asian and multiracial populations.
White (97.28%)
Other race (0.94%)
Two or more races (0.85%)
Black or African American (0.75%)
Asian (0.19%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 2,071 | 97.28% |
| Other race | 20 | 0.94% |
| Two or more races | 18 | 0.85% |
| Black or African American | 16 | 0.75% |
| Asian | 4 | 0.19% |
Married
Widowed
Divorced
Separated
Never Married
Sanford's average per capita income is $53,939. Household income levels show a median of $73,063. The poverty rate stands at 14.23%.
Name | Median | Mean |
|---|---|---|
| Married Families | $97,315 | - |
| Families | $89,643 | $109,045 |
| Households | $73,063 | $90,582 |
| Non Families | $37,550 | $46,191 |
Average Income
Median Household Income
Poverty Rate