Shenford is located in Ransom County, North Dakota. Shenford has a 2025 population of 110. Shenford is currently declining at a rate of -0.9% annually and its population has decreased by -3.51% since the most recent census, which recorded a population of 114 in 2020.
The average household income in Shenford is $206,486 with a poverty rate of 0%.The median age in Shenford is 30.5 years: 22.8 years for males, and 35.3 years for females.
Data after 2023 is projected based on recent change
The racial composition of Shenford includes 72.86% White, and smaller percentages for and multiracial populations.
White (72.9%)
Two or more races (27.1%)
Race | Population | Percentage (of total) |
---|---|---|
White | 51 | 72.86% |
Two or more races | 19 | 27.14% |
Married
Widowed
Divorced
Separated
Never Married
Shenford's average per capita income is $93,500. Household income levels show a median of $210,208. The poverty rate stands at 0%.
Name | Median | Mean |
---|---|---|
Families | $210,417 | $190,095 |
Households | $210,208 | $206,486 |
Married Families | $141,750 | - |
Non Families | - | - |
Average Income
Median Household Income
Poverty Rate