Shenford is located in Ransom County, North Dakota. Shenford has a 2025 population of 109 . Shenford is currently declining at a rate of -0.91% annually and its population has decreased by -3.54% since the most recent census, which recorded a population of 113 in 2020.
The average household income in Shenford is $206,486 with a poverty rate of 0%. The median age in Shenford is 30.5 years: 22.8 years for males, and 35.3 years for females. For every 100 females there are 169.2 males.
Data after 2023 is projected based on recent change
The racial composition of Shenford includes 72.86% White, and smaller percentages for and multiracial populations.
White (72.86%)
Two or more races (27.14%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 51 | 72.86% |
| Two or more races | 19 | 27.14% |
Married
Widowed
Divorced
Separated
Never Married
Shenford's average per capita income is $93,500. Household income levels show a median of $210,208. The poverty rate stands at 0%.
Name | Median | Mean |
|---|---|---|
| Families | $210,417 | $190,095 |
| Households | $210,208 | $206,486 |
| Married Families | $141,750 | - |
| Non Families | - | - |
Average Income
Median Household Income
Poverty Rate