Jefferson is a village located in Ashtabula County, Ohio. Jefferson has a 2025 population of 3,162. It is also the county seat of Ashtabula County. Jefferson is currently declining at a rate of -0.35% annually and its population has decreased by -1.68% since the most recent census, which recorded a population of 3,216 in 2020.
The average household income in Jefferson is $64,131 with a poverty rate of 12.55%.The median age in Jefferson is 55.2 years: 33.7 years for males, and 63.2 years for females.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 92.08% White, and smaller percentages for other race, Native Hawaiian or Pacific Islander, Black or African American and multiracial populations.
Race | Population | Percentage (of total) |
---|---|---|
White | 3,082 | 92.08% |
Two or more races | 134 | 4% |
Other race | 72 | 2.15% |
Native Hawaiian or Pacific Islander | 34 | 1.02% |
Black or African American | 25 | 0.75% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $50,920. Household income levels show a median of $47,469. The poverty rate stands at 12.55%.
Name | Median | Mean |
---|---|---|
Married Families | $88,965 | - |
Families | $88,164 | $91,798 |
Households | $47,469 | $64,131 |
Non Families | $29,318 | $40,846 |
Average Income
Median Household Income
Poverty Rate