Jefferson is located in Ashtabula County, Ohio. Jefferson has a 2025 population of 906 . It is also the county seat of Ashtabula County . Jefferson is currently growing at a rate of 0.22% annually and its population has increased by 0.44% since the most recent census, which recorded a population of 902 in 2020.
The average household income in Jefferson is $45,643 with a poverty rate of 15.91%. The median age in Jefferson is 57 years: 43.7 years for males, and 57.6 years for females. For every 100 females there are 140.6 males.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 98.1% White, and smaller percentages for Black or African American and multiracial populations.
White (98.1%)
Black or African American (1.9%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 413 | 98.1% |
| Black or African American | 8 | 1.9% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $39,625. Household income levels show a median of $41,250. The poverty rate stands at 15.91%.
Name | Median | Mean |
|---|---|---|
| Married Families | $49,318 | - |
| Families | $48,239 | $44,269 |
| Households | $41,250 | $45,643 |
| Non Families | - | $51,091 |
Average Income
Median Household Income
Poverty Rate