Jefferson is located in Ashtabula County, Ohio. Jefferson has a 2025 population of 3,511 . It is also the county seat of Ashtabula County . Jefferson is currently growing at a rate of 0.17% annually and its population has increased by 0.37% since the most recent census, which recorded a population of 3,498 in 2020.
The average household income in Jefferson is $76,506 with a poverty rate of 16.06%. The median age in Jefferson is 40 years: 43.1 years for males, and 33.6 years for females. For every 100 females there are 73.9 males.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 96.7% White, and smaller percentages for Black or African American, Two or more races, other race and multiracial populations.
White (96.7%)
Black or African American (2.09%)
Two or more races (1.15%)
Other race (0.06%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 3,373 | 96.7% |
| Black or African American | 73 | 2.09% |
| Two or more races | 40 | 1.15% |
| Other race | 2 | 0.06% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $52,602. Household income levels show a median of $58,929. The poverty rate stands at 16.06%.
Name | Median | Mean |
|---|---|---|
| Married Families | $103,418 | - |
| Families | $69,440 | $90,406 |
| Households | $58,929 | $76,506 |
| Non Families | $25,677 | $31,474 |
Average Income
Median Household Income
Poverty Rate