Jefferson is located in Ashtabula County, Ohio. Jefferson has a 2025 population of 4,963 . It is also the county seat of Ashtabula County . Jefferson is currently growing at a rate of 0.26% annually and its population has increased by 1.08% since the most recent census, which recorded a population of 4,910 in 2020.
The average household income in Jefferson is $83,084 with a poverty rate of 7.3%. The median age in Jefferson is 46.3 years: 45.5 years for males, and 46.8 years for females. For every 100 females there are 77.6 males.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 98.19% White, and smaller percentages for Black or African American, Two or more races, Asian, Native Hawaiian or Pacific Islander, other race and multiracial populations.
White (98.19%)
Black or African American (0.59%)
Two or more races (0.53%)
Asian (0.3%)
Native Hawaiian or Pacific Islander (0.2%)
Other race (0.18%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 4,839 | 98.19% |
| Black or African American | 29 | 0.59% |
| Two or more races | 26 | 0.53% |
| Asian | 15 | 0.3% |
| Native Hawaiian or Pacific Islander | 10 | 0.2% |
| Other race | 9 | 0.18% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $48,184. Household income levels show a median of $80,554. The poverty rate stands at 7.3%.
Name | Median | Mean |
|---|---|---|
| Married Families | $103,259 | - |
| Families | $99,367 | $100,168 |
| Households | $80,554 | $83,084 |
| Non Families | $39,395 | $46,207 |
Average Income
Median Household Income
Poverty Rate