Jefferson is located in Ashtabula County, Ohio. Jefferson has a 2025 population of 1,037 . It is also the county seat of Ashtabula County . Jefferson is currently declining at a rate of -0.19% annually and its population has decreased by -0.29% since the most recent census, which recorded a population of 1,040 in 2020.
The average household income in Jefferson is $67,619 with a poverty rate of 2.98%. The median age in Jefferson is 38.6 years: 50.4 years for males, and 29 years for females. For every 100 females there are 51.9 males.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 81.18% White, 9.13% other race, and smaller percentages for and multiracial populations.
White (81.18%)
Two or more races (9.69%)
Other race (9.13%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 1,165 | 81.18% |
| Two or more races | 139 | 9.69% |
| Other race | 131 | 9.13% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $45,533. Household income levels show a median of $60,625. The poverty rate stands at 2.98%.
Name | Median | Mean |
|---|---|---|
| Married Families | $101,557 | - |
| Families | $79,205 | $78,438 |
| Households | $60,625 | $67,619 |
| Non Families | $46,279 | $47,334 |
Average Income
Median Household Income
Poverty Rate