Selinsgrove is a borough located in Snyder County, Pennsylvania Pennsylvania. Unfortunately, the data for this location is currently limited or unavailable.
The average household income in Selinsgrove is $70,262 with a poverty rate of 7.74%. The median age in Selinsgrove is 24.4 years: 26.2 years for males, and 23.2 years for females. For every 100 females there are 94.9 males.
No data available.
The racial composition of Selinsgrove includes 87.64% White, 4.23% Black or African American, and smaller percentages for Native Hawaiian or Pacific Islander, Asian, other race, Native American and multiracial populations.
White (87.64%)
Two or more races (4.63%)
Black or African American (4.23%)
Native Hawaiian or Pacific Islander (1.41%)
Asian (1.01%)
Other race (1.01%)
Native American (0.07%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 4,956 | 87.64% |
| Two or more races | 262 | 4.63% |
| Black or African American | 239 | 4.23% |
| Native Hawaiian or Pacific Islander | 80 | 1.41% |
| Asian | 57 | 1.01% |
| Other race | 57 | 1.01% |
| Native American | 4 | 0.07% |
Married
Widowed
Divorced
Separated
Never Married
Selinsgrove's average per capita income is $42,857. Household income levels show a median of $58,484. The poverty rate stands at 7.74%.
Name | Median | Mean |
|---|---|---|
| Married Families | $105,699 | - |
| Families | $88,828 | $95,100 |
| Households | $58,484 | $70,262 |
| Non Families | $36,836 | $50,382 |
Average Income
Median Household Income
Poverty Rate