Ten Sleep is a town located in Washakie County, Wyoming. Ten Sleep has a 2025 population of 264 . Ten Sleep is currently growing at a rate of 0.76% annually and its population has increased by 4.35% since the most recent census, which recorded a population of 253 in 2020.
The average household income in Ten Sleep is $46,003 with a poverty rate of 37.38%. The median age in Ten Sleep is 54.5 years: 23.6 years for males, and 61.9 years for females. For every 100 females there are 161.0 males.
Data after 2023 is projected based on recent change
The racial composition of Ten Sleep includes 88.79% White, and smaller percentages for Asian and multiracial populations.
White (88.79%)
Two or more races (10.28%)
Asian (0.93%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 190 | 88.79% |
| Two or more races | 22 | 10.28% |
| Asian | 2 | 0.93% |
Married
Widowed
Divorced
Separated
Never Married
Ten Sleep's average per capita income is $21,250. Household income levels show a median of $30,893. The poverty rate stands at 37.38%.
Name | Median | Mean |
|---|---|---|
| Married Families | $108,438 | - |
| Households | $30,893 | $46,003 |
| Non Families | $24,667 | $34,868 |
| Families | - | $61,002 |
Average Income
Median Household Income
Poverty Rate