Ten Sleep is a town located in Washakie County, Wyoming. Ten Sleep has a 2026 population of 266. Ten Sleep is currently growing at a rate of 0.76% annually and its population has increased by 5.14% since the most recent census, which recorded a population of 253 in 2020.
The median household income in Ten Sleep is $46,875 with a poverty rate of 21.76%. The median age in Ten Sleep is 61.1 years: 54 years for males, and 62 years for females. For every 100 females there are 111.5 males.
Data after 2023 is projected based on recent change
Overall: 61.1 years
Female: 62 years
Male: 54 years
There are 206 adults, (100 of whom are seniors) in Ten Sleep.
Female: 113 (47.3%)
Male: 126 (52.7%)
The racial composition of Ten Sleep includes 82.01% White, and smaller percentages for Asian and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 196 | 82.01% |
| Two or more races | 41 | 17.15% |
| Asian | 2 | 0.84% |
Ten Sleep 's average per capita income is $75,833. Household income levels show a median of $46,875. The poverty rate stands at 21.76%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $115,313 | - |
| Families | $111,000 | $120,046 |
| Households | $46,875 | $81,697 |
| Non Families | $42,589 | $55,484 |
Average Income
Median Household Income
Poverty Rate