Seward township is located in Kosciusko County, Indiana. Seward township has a 2025 population of 2,272. Seward township is currently declining at a rate of -0.39% annually and its population has decreased by -0.83% since the most recent census, which recorded a population of 2,291 in 2020.
The average household income in Seward township is $100,423 with a poverty rate of 7.9%.The median age in Seward township is 51 years: 45.5 years for males, and 55.6 years for females.
Data after 2023 is projected based on recent change
The racial composition of Seward township includes 91.72% White, 5.14% other race, and smaller percentages for Two or more races, Black or African American and multiracial populations.
Race | Population | Percentage (of total) |
---|---|---|
White | 2,159 | 91.72% |
Other race | 121 | 5.14% |
Two or more races | 52 | 2.21% |
Black or African American | 22 | 0.93% |
Married
Widowed
Divorced
Separated
Never Married
Seward township's average per capita income is $54,931. Household income levels show a median of $74,794. The poverty rate stands at 7.9%.
Name | Median | Mean |
---|---|---|
Married Families | $101,446 | - |
Families | $99,028 | $118,979 |
Households | $74,794 | $100,423 |
Non Families | $37,212 | $53,207 |
Average Income
Median Household Income
Poverty Rate