Seward is located in Kosciusko County, Indiana. Seward has a 2025 population of 2,311 . Seward is currently growing at a rate of 0.43% annually and its population has increased by 0.78% since the most recent census, which recorded a population of 2,293 in 2020.
The average household income in Seward is $100,423 with a poverty rate of 7.9%. The median age in Seward is 51 years: 45.5 years for males, and 55.6 years for females. For every 100 females there are 114.0 males.
Data after 2023 is projected based on recent change
The racial composition of Seward includes 91.72% White, 5.14% other race, and smaller percentages for Two or more races, Black or African American and multiracial populations.
White (91.72%)
Other race (5.14%)
Two or more races (2.21%)
Black or African American (0.93%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 2,159 | 91.72% |
| Other race | 121 | 5.14% |
| Two or more races | 52 | 2.21% |
| Black or African American | 22 | 0.93% |
Married
Widowed
Divorced
Separated
Never Married
Seward's average per capita income is $54,931. Household income levels show a median of $74,794. The poverty rate stands at 7.9%.
Name | Median | Mean |
|---|---|---|
| Married Families | $101,446 | - |
| Families | $99,028 | $118,979 |
| Households | $74,794 | $100,423 |
| Non Families | $37,212 | $53,207 |
Average Income
Median Household Income
Poverty Rate